It’s not a dream. Am I right?

I’ve created an application to reinvent the R-sequence and analyze the newly introduced B-sequence (ie. sequence that describes consecutive blockers within R-sequence). Everything but one thing works perfect, ie. everything but 2640 (which should be 2624; both numbers have dimension equal to 7, which proves that my app has some leak, thus I won’t be able to shed enough light on B-sequence in this post).

Enclosed. (as a JPG file, you need to change extension to .exe).

https://mishabucko.files.wordpress.com/2011/12/app.jpg

Output of the app (currently with issues), below (also as a JPG file):

https://mishabucko.files.wordpress.com/2011/12/info.jpg

The interesting thing I had noticed is that B-sequence starts with 1,2,3,6,9,16, which resembles Fibonacci sequence. If we subtract 1 from each of the factors, then we have 1,2,5,8,15, where 1+2+5=8 and 2+5+8=15, making F_n=F_{n-3}+F_{n-2}+F_{n-1} an interesting hint. According to the app’s current state of art, it doesn’t looke like we’ve got “easy” solutions.

Another interesting thing is that fraction of (n+1)th and (n)th blocker, ie. {{10}\over{3}},{{30}\over{10}},{{104}\over{30}},{{312}\over{104}}, {{1040}\over{312}} looks extremely synesthetic, if I could put it this way. Firstly, very close to pi, secondly – a lot of repetition involved (easily noticable).

Another question regarding R-sequence: we know 3^n plays such a significant role- what about 5^n,7^n, etc.

Below, short update on investment equity with significantly large sample size.

 

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About misha

Imagine a story that one can't believe. Hi. Life changes here. Small things only.
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